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Message Subject Calling Astro...Please come in and explain how this works???..It's freaking me out.....
Poster Handle leader
Post Content
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The moon is moving fast relative to the a line between the sun and earth.
 Quoting: leader

A poster above possibly OP calculated the two variables as such:
Instantaneous velocity of point at surface of the earth ~1000mph.
Instantaneous velocity of (centre of) moon at point of circumference of rotation around the earth ~2600mph.
If we consider the instant that a line from the centre of the sun, through the centre of the moon to that point on the ground occurs, we can model the basic physics without need to consider parallax, angular velocity or any complicating factors.
Instantaneously the point on the ground is moving west to east at 1000mph.
At the same instant the centre of the moon is moving west to east at 2600mph. An hour later, the same line centre of sun through centre of the moon should now be at a point ~1600m east of the first point etc.
We can project roughly this process to continue for the entire set of instances that the eclipse includes, giving the shadow the appearance of moving west to east at ~1600mph.
I am unsure whether OP is stirring or not, but surely if it means that much to the respondents that you would be hurling abuse, then you could make a simplistic yet accurate description?
There are actual real issues out there guys, why waste yourselves in combat in such a distraction?
 Quoting: Anonymous Coward 80000801


Wrong, the angular speed is what matters in this case. The angular speed of the rotation of the earth 2(pi)/1 day is much greater than the angular speed of the moon around the earth 2(pi)/27.3 days. In your example, the line through the center of the earth and moon would intersect the earth to the west of its initial point of intersection.
 Quoting: leader


Yes you are deliberately complicating the issue. There is no need to consider the centre of the earth as the moon's shadow falls on the surface of the earth. If you read my answer you would note that I never mentioned the centre of the earth. Keep it simple, model a line centre of the sun through centre of moon to surface of the earth. It is the instantaneous velocities that count in this instance.
 Quoting: Anonymous Coward 80000801


Wrong, I am simplifying it. I am considering the simplest case when the Earth Moon Sun are all on the same plane. In that case the line will go through the centers of the three objects. And as I have proven, in that case the shadow will move from East to West. What have you shown? You have shown nothing; all you have done is stated something without proof. Do you have a proof for your claim?


I have no skin in the game.
Enjoy your logical fallacy.


Point out the fallacy in my logic please.
 
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