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Calling Astro...Please come in and explain how this works???..It's freaking me out.....

 
leader

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02/22/2021 07:45 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
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Wow, that video it totally misleading. The speed of the objects is not what matters in this case, what matters is the angular speed. In the case of the angular speed of the rotation of the Earth, it is 2(pi)/(1 day), in the case of the moon it is 2(pi)/(27.3 days)

Angular speed of the rotation of the earth much greater than the angular speed of the moon. DONE!

Stop watching fake science, it makes you stupid.
 Quoting: leader

This subject has no reason to divulge to the level of acrimony shown here, and provocation is as bad as reaction.
However, there is a simple and correct answer. I will not watch your videos, however we should all be able to envision the correct model to realise the truth, outlined simply as such:
 Quoting: shrike 80000801

The moon is moving fast relative to the a line between the sun and earth.
 Quoting: leader

A poster above possibly OP calculated the two variables as such:
Instantaneous velocity of point at surface of the earth ~1000mph.
Instantaneous velocity of (centre of) moon at point of circumference of rotation around the earth ~2600mph.
If we consider the instant that a line from the centre of the sun, through the centre of the moon to that point on the ground occurs, we can model the basic physics without need to consider parallax, angular velocity or any complicating factors.
Instantaneously the point on the ground is moving west to east at 1000mph.
At the same instant the centre of the moon is moving west to east at 2600mph. An hour later, the same line centre of sun through centre of the moon should now be at a point ~1600m east of the first point etc.
We can project roughly this process to continue for the entire set of instances that the eclipse includes, giving the shadow the appearance of moving west to east at ~1600mph.
I am unsure whether OP is stirring or not, but surely if it means that much to the respondents that you would be hurling abuse, then you could make a simplistic yet accurate description?
There are actual real issues out there guys, why waste yourselves in combat in such a distraction?
 Quoting: Anonymous Coward 80000801


Wrong, the angular speed is what matters in this case. The angular speed of the rotation of the earth 2(pi)/1 day is much greater than the angular speed of the moon around the earth 2(pi)/27.3 days. In your example, the line through the center of the earth and moon would intersect the earth to the west of its initial point of intersection.


Yes you are deliberately complicating the issue. There is no need to consider the centre of the earth as the moon's shadow falls on the surface of the earth. If you read my answer you would note that I never mentioned the centre of the earth. Keep it simple, model a line centre of the sun through centre of moon to surface of the earth. It is the instantaneous velocities that count in this instance.


Wrong, I am simplifying it. I am considering the simplest case when the Earth Moon Sun are all on the same plane. In that case the line will go through the centers of the three objects. And as I have proven, in that case the shadow will move from East to West. What have you shown? You have shown nothing; all you have done is stated something without proof. Do you have a proof for your claim?
jack
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02/22/2021 07:50 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
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This subject has no reason to divulge to the level of acrimony shown here, and provocation is as bad as reaction.
However, there is a simple and correct answer. I will not watch your videos, however we should all be able to envision the correct model to realise the truth, outlined simply as such:
 Quoting: shrike 80000801

The moon is moving fast relative to the a line between the sun and earth.
 Quoting: leader

A poster above possibly OP calculated the two variables as such:
Instantaneous velocity of point at surface of the earth ~1000mph.
Instantaneous velocity of (centre of) moon at point of circumference of rotation around the earth ~2600mph.
If we consider the instant that a line from the centre of the sun, through the centre of the moon to that point on the ground occurs, we can model the basic physics without need to consider parallax, angular velocity or any complicating factors.
Instantaneously the point on the ground is moving west to east at 1000mph.
At the same instant the centre of the moon is moving west to east at 2600mph. An hour later, the same line centre of sun through centre of the moon should now be at a point ~1600m east of the first point etc.
We can project roughly this process to continue for the entire set of instances that the eclipse includes, giving the shadow the appearance of moving west to east at ~1600mph.
I am unsure whether OP is stirring or not, but surely if it means that much to the respondents that you would be hurling abuse, then you could make a simplistic yet accurate description?
There are actual real issues out there guys, why waste yourselves in combat in such a distraction?
 Quoting: Anonymous Coward 80000801


Wrong, the angular speed is what matters in this case. The angular speed of the rotation of the earth 2(pi)/1 day is much greater than the angular speed of the moon around the earth 2(pi)/27.3 days. In your example, the line through the center of the earth and moon would intersect the earth to the west of its initial point of intersection.
 Quoting: leader


Yes you are deliberately complicating the issue. There is no need to consider the centre of the earth as the moon's shadow falls on the surface of the earth. If you read my answer you would note that I never mentioned the centre of the earth. Keep it simple, model a line centre of the sun through centre of moon to surface of the earth. It is the instantaneous velocities that count in this instance.


Wrong, I am simplifying it. I am considering the simplest case when the Earth Moon Sun are all on the same plane. In that case the line will go through the centers of the three objects. And as I have proven, in that case the shadow will move from East to West. What have you shown? You have shown nothing; all you have done is stated something without proof. Do you have a proof for your claim?


I have no skin in the game.
Enjoy your logical fallacy.
Anonymous Coward
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Australia
02/22/2021 07:50 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
...

This subject has no reason to divulge to the level of acrimony shown here, and provocation is as bad as reaction.
However, there is a simple and correct answer. I will not watch your videos, however we should all be able to envision the correct model to realise the truth, outlined simply as such:
 Quoting: shrike 80000801

The moon is moving fast relative to the a line between the sun and earth.
 Quoting: leader

A poster above possibly OP calculated the two variables as such:
Instantaneous velocity of point at surface of the earth ~1000mph.
Instantaneous velocity of (centre of) moon at point of circumference of rotation around the earth ~2600mph.
If we consider the instant that a line from the centre of the sun, through the centre of the moon to that point on the ground occurs, we can model the basic physics without need to consider parallax, angular velocity or any complicating factors.
Instantaneously the point on the ground is moving west to east at 1000mph.
At the same instant the centre of the moon is moving west to east at 2600mph. An hour later, the same line centre of sun through centre of the moon should now be at a point ~1600m east of the first point etc.
We can project roughly this process to continue for the entire set of instances that the eclipse includes, giving the shadow the appearance of moving west to east at ~1600mph.
I am unsure whether OP is stirring or not, but surely if it means that much to the respondents that you would be hurling abuse, then you could make a simplistic yet accurate description?
There are actual real issues out there guys, why waste yourselves in combat in such a distraction?
 Quoting: Anonymous Coward 80000801


Wrong, the angular speed is what matters in this case. The angular speed of the rotation of the earth 2(pi)/1 day is much greater than the angular speed of the moon around the earth 2(pi)/27.3 days. In your example, the line through the center of the earth and moon would intersect the earth to the west of its initial point of intersection.
 Quoting: leader


Yes you are deliberately complicating the issue. There is no need to consider the centre of the earth as the moon's shadow falls on the surface of the earth. If you read my answer you would note that I never mentioned the centre of the earth. Keep it simple, model a line centre of the sun through centre of moon to surface of the earth. It is the instantaneous velocities that count in this instance.


Wrong, I am simplifying it. I am considering the simplest case when the Earth Moon Sun are all on the same plane. In that case the line will go through the centers of the three objects. And as I have proven, in that case the shadow will move from East to West. What have you shown? You have shown nothing; all you have done is stated something without proof. Do you have a proof for your claim?


I have no skin in the game.
Enjoy your logical fallacy.
leader

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United States
02/22/2021 07:51 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
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The moon is moving fast relative to the a line between the sun and earth.
 Quoting: leader

A poster above possibly OP calculated the two variables as such:
Instantaneous velocity of point at surface of the earth ~1000mph.
Instantaneous velocity of (centre of) moon at point of circumference of rotation around the earth ~2600mph.
If we consider the instant that a line from the centre of the sun, through the centre of the moon to that point on the ground occurs, we can model the basic physics without need to consider parallax, angular velocity or any complicating factors.
Instantaneously the point on the ground is moving west to east at 1000mph.
At the same instant the centre of the moon is moving west to east at 2600mph. An hour later, the same line centre of sun through centre of the moon should now be at a point ~1600m east of the first point etc.
We can project roughly this process to continue for the entire set of instances that the eclipse includes, giving the shadow the appearance of moving west to east at ~1600mph.
I am unsure whether OP is stirring or not, but surely if it means that much to the respondents that you would be hurling abuse, then you could make a simplistic yet accurate description?
There are actual real issues out there guys, why waste yourselves in combat in such a distraction?
 Quoting: Anonymous Coward 80000801


Wrong, the angular speed is what matters in this case. The angular speed of the rotation of the earth 2(pi)/1 day is much greater than the angular speed of the moon around the earth 2(pi)/27.3 days. In your example, the line through the center of the earth and moon would intersect the earth to the west of its initial point of intersection.
 Quoting: leader


Yes you are deliberately complicating the issue. There is no need to consider the centre of the earth as the moon's shadow falls on the surface of the earth. If you read my answer you would note that I never mentioned the centre of the earth. Keep it simple, model a line centre of the sun through centre of moon to surface of the earth. It is the instantaneous velocities that count in this instance.
 Quoting: Anonymous Coward 80000801


Wrong, I am simplifying it. I am considering the simplest case when the Earth Moon Sun are all on the same plane. In that case the line will go through the centers of the three objects. And as I have proven, in that case the shadow will move from East to West. What have you shown? You have shown nothing; all you have done is stated something without proof. Do you have a proof for your claim?


I have no skin in the game.
Enjoy your logical fallacy.


Point out the fallacy in my logic please.
jack
sunwatcher

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02/22/2021 08:17 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
I don't know what shape the earth is nor do I know the true nature of reality, but I do know a couple things: NASA is full of shit and always has been, and the earth is NOT a sphere.
 Quoting: Anonymous Coward 75012624


Yup, not a sphere. It's a GEOID.
Anonymous Coward
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02/22/2021 08:18 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
Wow, yet another nail in the coffin for the globe earth theory.

Shills be baiting this thread hard.
Yuck Fou

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02/22/2021 08:22 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
Watch this.

Anonymous Coward
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02/22/2021 08:37 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
The Moon passes the sun at a speed of 1+ km/s ~ 2300 mph. The Earth rotates at 1000 mph at the surface, the moon orbits the same direction as Earth spins, so the effective shadow speed across the surface is less and varies with each eclipse, but always more than 1000 mph.

Note the Moon orbiting the same direction as Earth spins, meaning the shadow will move from west to east.


So. That's my high school dropout explanation, anyways
Anonymous Coward
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02/22/2021 08:40 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
Wow, yet another nail in the coffin for the globe earth theory.
 Quoting: Anonymous Coward 76754146



norespect
leader

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02/22/2021 08:41 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
The Moon passes the sun at a speed of 1+ km/s ~ 2300 mph. The Earth rotates at 1000 mph at the surface, the moon orbits the same direction as Earth spins, so the effective shadow speed across the surface is less and varies with each eclipse, but always more than 1000 mph.

Note the Moon orbiting the same direction as Earth spins, meaning the shadow will move from west to east.


So. That's my high school dropout explanation, anyways
 Quoting: Anonymous Coward 80045380


The angular speed of the rotation of the Earth is much greater than the angular speed of the moon rotating around the Earth. So in fact, the shadow will go from East to West if the ball model is reality.
jack
EequalsMC2

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02/22/2021 08:48 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
These flat earth tards literally have nothing going for them in life. They sit on their iPads all day eating hot pockets while trying to convince you that most mountains and rocks used to be living people. I refuse to engage with them in the slightest. I feel for the parents and possible future offspring of these people.
leader

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02/22/2021 08:51 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
These flat earth tards literally have nothing going for them in life. They sit on their iPads all day eating hot pockets while trying to convince you that most mountains and rocks used to be living people. I refuse to engage with them in the slightest. I feel for the parents and possible future offspring of these people.
 Quoting: EequalsMC2


Is that a debunk of my proof?
jack
Anonymous Coward
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02/22/2021 08:55 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
The earth is not a ball.

Railgun is a perfect proof.
There is no missile technology in it and it can shoot to 100miles ship to ship.

Its based on high speed of the ammo.
That ammo would need to adjust the curve of the earth with a 1,2miles drop

Water seeks its level
leader

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02/22/2021 09:07 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
The earth is not a ball.

Railgun is a perfect proof.
There is no missile technology in it and it can shoot to 100miles ship to ship.

Its based on high speed of the ammo.
That ammo would need to adjust the curve of the earth with a 1,2miles drop

Water seeks its level
 Quoting: Anonymous Coward 77823945


And the list of proofs goes on and on and on, doesn't it.
jack
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02/22/2021 09:10 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....


The moon is moving fast relative to the a line between the sun and earth.
 Quoting: Beneneth


Everyone should be able to understand how this works from this video.

The moon has to travel a tiny fraction of it's orbit in order to travel across the sun.

It should be pretty obvious.
leader

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02/22/2021 09:13 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....


The moon is moving fast relative to the a line between the sun and earth.
 Quoting: Beneneth


Everyone should be able to understand how this works from this video.

The moon has to travel a tiny fraction of it's orbit in order to travel across the sun.

It should be pretty obvious.
 Quoting: Anonymous Coward 78954816


Sorry? Are you trying to say something?
jack
Anonymous Coward
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02/22/2021 09:18 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....


The moon is moving fast relative to the a line between the sun and earth.
 Quoting: Beneneth


Everyone should be able to understand how this works from this video.

The moon has to travel a tiny fraction of it's orbit in order to travel across the sun.

It should be pretty obvious.
 Quoting: Anonymous Coward 78954816


Sorry? Are you trying to say something?
 Quoting: leader


That video explains in easy to understand terms why the place where you can see solar eclipse travels from west to east.

It's quite simple, really. So there's no need to argue over it.
Anonymous Coward
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02/22/2021 09:20 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
Wow, yet another nail in the coffin for the globe earth theory.
 Quoting: Anonymous Coward 76754146



norespect
 Quoting: Anonymous Coward 80045380


I guess you didn’t watch the video...it is certainly a nail in the coffin for globe earth theory...
leader

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02/22/2021 09:24 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....


The moon is moving fast relative to the a line between the sun and earth.
 Quoting: Beneneth


Everyone should be able to understand how this works from this video.

The moon has to travel a tiny fraction of it's orbit in order to travel across the sun.

It should be pretty obvious.
 Quoting: Anonymous Coward 78954816


Sorry? Are you trying to say something?
 Quoting: leader


That video explains in easy to understand terms why the place where you can see solar eclipse travels from west to east.

It's quite simple, really. So there's no need to argue over it.
 Quoting: Anonymous Coward 78954816


I already proved that the video is wrong because the speed of the Earth and moon doesn't matter in this case, what matters is the angular speed of Earth's rotation and the angular speed of the moon's orbit around the earth. Did you not read my proof?
jack
Anonymous Alien

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02/22/2021 10:20 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
I suppose you would not only need to consider the speed of Earth's rotation, and the speed and direction of the moon in relation to Earth, but also of the Earth's orbit around the sun which is a considerable speed.
Anonymous Coward
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02/22/2021 10:20 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
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Everyone should be able to understand how this works from this video.

The moon has to travel a tiny fraction of it's orbit in order to travel across the sun.

It should be pretty obvious.
 Quoting: Anonymous Coward 78954816


Sorry? Are you trying to say something?
 Quoting: leader


That video explains in easy to understand terms why the place where you can see solar eclipse travels from west to east.

It's quite simple, really. So there's no need to argue over it.
 Quoting: Anonymous Coward 78954816


I already proved that the video is wrong because the speed of the Earth and moon doesn't matter in this case, what matters is the angular speed of Earth's rotation and the angular speed of the moon's orbit around the earth. Did you not read my proof?
 Quoting: leader


I tried to read everything but I didn't quite get what you meant by that.

The only thing that matters in my opinion is how fast the Earth rotates and how fast the Moon goes by that portion of its orbit where it's blocking at least some portion of the Sun from view on Earth.

If you think about it, the Moon is just able to cover the Sun when a total eclipse is happening. So for a rough estimate, we can calculate the moon's diameter times two for the distance the Moon is covering at least some part of the sun when viewed from Earth. So all we have to do is take the Moon's diameter times two and divide it by the speed per hour the Moon is traveling at and that will tell us the time it takes for the Moon to travel across the Sun.

So we'll take The Moon diameter and multiply it by two 3 474,2 km * 2 = 6 948,4 km and divide that by the speed of the Moon 6948,4 km / 3,700 km = 3,700 = 1,878 and that is how many hours roughly it would take for the Moon to go across the Sun if viewed from a single non-rotating point on Earth. The rotation of course makes the time a bit longer as the same point on Earth is traveling in the same general direction with the Moon.

So that's my take on it and I'm fairly sure that's in the ballpark for this type of an example. You can see how the two hours of partial eclipse is faster than the rotation of the Earth and that's why the eclipse moves from West to East.
leader

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02/22/2021 10:45 AM

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Sorry? Are you trying to say something?
 Quoting: leader


That video explains in easy to understand terms why the place where you can see solar eclipse travels from west to east.

It's quite simple, really. So there's no need to argue over it.
 Quoting: Anonymous Coward 78954816


I already proved that the video is wrong because the speed of the Earth and moon doesn't matter in this case, what matters is the angular speed of Earth's rotation and the angular speed of the moon's orbit around the earth. Did you not read my proof?
 Quoting: leader


I tried to read everything but I didn't quite get what you meant by that.

The only thing that matters in my opinion is how fast the Earth rotates and how fast the Moon goes by that portion of its orbit where it's blocking at least some portion of the Sun from view on Earth.

If you think about it, the Moon is just able to cover the Sun when a total eclipse is happening. So for a rough estimate, we can calculate the moon's diameter times two for the distance the Moon is covering at least some part of the sun when viewed from Earth. So all we have to do is take the Moon's diameter times two and divide it by the speed per hour the Moon is traveling at and that will tell us the time it takes for the Moon to travel across the Sun.

So we'll take The Moon diameter and multiply it by two 3 474,2 km * 2 = 6 948,4 km and divide that by the speed of the Moon 6948,4 km / 3,700 km = 3,700 = 1,878 and that is how many hours roughly it would take for the Moon to go across the Sun if viewed from a single non-rotating point on Earth. The rotation of course makes the time a bit longer as the same point on Earth is traveling in the same general direction with the Moon.

So that's my take on it and I'm fairly sure that's in the ballpark for this type of an example. You can see how the two hours of partial eclipse is faster than the rotation of the Earth and that's why the eclipse moves from West to East.
 Quoting: Anonymous Coward 78954816


The issue is this. A point on the Earth is travelling at 15 degrees per hour due to the rotation of the Earth, that is its angular speed. The moon in its orbit around the earth travels at 0.6 degrees per hour, again its angular speed. So if the Earth did not spin, the moon's shadow would certainly move from West to East, but since the Earth rotates through many more degrees per unit time than the moon in its orbit around the Earth, the Earth wins the race and therefore spins ahead of the moon's shadow, and therefore it will appear that the moon's shadow is traveling from East to West.
jack
Beneneth

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02/22/2021 11:12 AM

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That video explains in easy to understand terms why the place where you can see solar eclipse travels from west to east.

It's quite simple, really. So there's no need to argue over it.
 Quoting: Anonymous Coward 78954816


I already proved that the video is wrong because the speed of the Earth and moon doesn't matter in this case, what matters is the angular speed of Earth's rotation and the angular speed of the moon's orbit around the earth. Did you not read my proof?
 Quoting: leader


I tried to read everything but I didn't quite get what you meant by that.

The only thing that matters in my opinion is how fast the Earth rotates and how fast the Moon goes by that portion of its orbit where it's blocking at least some portion of the Sun from view on Earth.

If you think about it, the Moon is just able to cover the Sun when a total eclipse is happening. So for a rough estimate, we can calculate the moon's diameter times two for the distance the Moon is covering at least some part of the sun when viewed from Earth. So all we have to do is take the Moon's diameter times two and divide it by the speed per hour the Moon is traveling at and that will tell us the time it takes for the Moon to travel across the Sun.

So we'll take The Moon diameter and multiply it by two 3 474,2 km * 2 = 6 948,4 km and divide that by the speed of the Moon 6948,4 km / 3,700 km = 3,700 = 1,878 and that is how many hours roughly it would take for the Moon to go across the Sun if viewed from a single non-rotating point on Earth. The rotation of course makes the time a bit longer as the same point on Earth is traveling in the same general direction with the Moon.

So that's my take on it and I'm fairly sure that's in the ballpark for this type of an example. You can see how the two hours of partial eclipse is faster than the rotation of the Earth and that's why the eclipse moves from West to East.
 Quoting: Anonymous Coward 78954816


The issue is this. A point on the Earth is travelling at 15 degrees per hour due to the rotation of the Earth, that is its angular speed. The moon in its orbit around the earth travels at 0.6 degrees per hour, again its angular speed. So if the Earth did not spin, the moon's shadow would certainly move from West to East, but since the Earth rotates through many more degrees per unit time than the moon in its orbit around the Earth, the Earth wins the race and therefore spins ahead of the moon's shadow, and therefore it will appear that the moon's shadow is traveling from East to West.
 Quoting: leader


You are confusing the moon and its shadow. Its shadow moves much quicker.
Jesus is Lord
Anonymous Coward
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02/22/2021 11:12 AM
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That video explains in easy to understand terms why the place where you can see solar eclipse travels from west to east.

It's quite simple, really. So there's no need to argue over it.
 Quoting: Anonymous Coward 78954816


I already proved that the video is wrong because the speed of the Earth and moon doesn't matter in this case, what matters is the angular speed of Earth's rotation and the angular speed of the moon's orbit around the earth. Did you not read my proof?
 Quoting: leader


I tried to read everything but I didn't quite get what you meant by that.

The only thing that matters in my opinion is how fast the Earth rotates and how fast the Moon goes by that portion of its orbit where it's blocking at least some portion of the Sun from view on Earth.

If you think about it, the Moon is just able to cover the Sun when a total eclipse is happening. So for a rough estimate, we can calculate the moon's diameter times two for the distance the Moon is covering at least some part of the sun when viewed from Earth. So all we have to do is take the Moon's diameter times two and divide it by the speed per hour the Moon is traveling at and that will tell us the time it takes for the Moon to travel across the Sun.

So we'll take The Moon diameter and multiply it by two 3 474,2 km * 2 = 6 948,4 km and divide that by the speed of the Moon 6948,4 km / 3,700 km = 3,700 = 1,878 and that is how many hours roughly it would take for the Moon to go across the Sun if viewed from a single non-rotating point on Earth. The rotation of course makes the time a bit longer as the same point on Earth is traveling in the same general direction with the Moon.

So that's my take on it and I'm fairly sure that's in the ballpark for this type of an example. You can see how the two hours of partial eclipse is faster than the rotation of the Earth and that's why the eclipse moves from West to East.
 Quoting: Anonymous Coward 78954816


The issue is this. A point on the Earth is travelling at 15 degrees per hour due to the rotation of the Earth, that is its angular speed. The moon in its orbit around the earth travels at 0.6 degrees per hour, again its angular speed. So if the Earth did not spin, the moon's shadow would certainly move from West to East, but since the Earth rotates through many more degrees per unit time than the moon in its orbit around the Earth, the Earth wins the race and therefore spins ahead of the moon's shadow, and therefore it will appear that the moon's shadow is traveling from East to West.
 Quoting: leader


But the Moon doesn't have to "win the race". It just has to go by the Sun. The Sun isn't that big and if you think about your field of view when looking up at the sky, the Sun doesn't take up many degrees of your vertical field of view. It actually takes about 0.5 degrees.

Now if the moon goes roughly 0.54 degrees of its orbit per hour it doesn't take long to pass by the Sun. You can actually do the same calculation as I did before with kilometers but with degrees (distance 0.5 * 2 divided by speed 0.54) and it's pretty close to the same answer as before.

You can see how going by the Sun in two hours or so would be much faster than the speed at which the Earth is rotating, right?
Beneneth

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02/22/2021 11:15 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
There is a nice piece of software called 'Celestia' which you can actually enter the date and rotate around the earth/moon/sun in 3d (and the rest of the galaxy if you wish) and you can see how the shadow moves over the earth, pause, look at the positions etc.

You can watch for yourself why it happens.

[link to celestia.space (secure)]
Jesus is Lord
leader

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02/22/2021 11:44 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
...


I already proved that the video is wrong because the speed of the Earth and moon doesn't matter in this case, what matters is the angular speed of Earth's rotation and the angular speed of the moon's orbit around the earth. Did you not read my proof?
 Quoting: leader


I tried to read everything but I didn't quite get what you meant by that.

The only thing that matters in my opinion is how fast the Earth rotates and how fast the Moon goes by that portion of its orbit where it's blocking at least some portion of the Sun from view on Earth.

If you think about it, the Moon is just able to cover the Sun when a total eclipse is happening. So for a rough estimate, we can calculate the moon's diameter times two for the distance the Moon is covering at least some part of the sun when viewed from Earth. So all we have to do is take the Moon's diameter times two and divide it by the speed per hour the Moon is traveling at and that will tell us the time it takes for the Moon to travel across the Sun.

So we'll take The Moon diameter and multiply it by two 3 474,2 km * 2 = 6 948,4 km and divide that by the speed of the Moon 6948,4 km / 3,700 km = 3,700 = 1,878 and that is how many hours roughly it would take for the Moon to go across the Sun if viewed from a single non-rotating point on Earth. The rotation of course makes the time a bit longer as the same point on Earth is traveling in the same general direction with the Moon.

So that's my take on it and I'm fairly sure that's in the ballpark for this type of an example. You can see how the two hours of partial eclipse is faster than the rotation of the Earth and that's why the eclipse moves from West to East.
 Quoting: Anonymous Coward 78954816


The issue is this. A point on the Earth is travelling at 15 degrees per hour due to the rotation of the Earth, that is its angular speed. The moon in its orbit around the earth travels at 0.6 degrees per hour, again its angular speed. So if the Earth did not spin, the moon's shadow would certainly move from West to East, but since the Earth rotates through many more degrees per unit time than the moon in its orbit around the Earth, the Earth wins the race and therefore spins ahead of the moon's shadow, and therefore it will appear that the moon's shadow is traveling from East to West.
 Quoting: leader


But the Moon doesn't have to "win the race". It just has to go by the Sun. The Sun isn't that big and if you think about your field of view when looking up at the sky, the Sun doesn't take up many degrees of your vertical field of view. It actually takes about 0.5 degrees.

Now if the moon goes roughly 0.54 degrees of its orbit per hour it doesn't take long to pass by the Sun. You can actually do the same calculation as I did before with kilometers but with degrees (distance 0.5 * 2 divided by speed 0.54) and it's pretty close to the same answer as before.

You can see how going by the Sun in two hours or so would be much faster than the speed at which the Earth is rotating, right?
 Quoting: Anonymous Coward 78954816


Wrong. Do this. Draw two concentric circles. The inner circle represents the earth's surface circle; think of it as the equator circle. And the outer circle is the moons path. And think of it as looking down at it from the north pole direction. Now draw a dot outside both of the circles to represent the sun. Now draw a line that connects the center of the two concentric circles with the dot that represents the sun. That line will intersect the Earth circle where the shadow begins and the outer circle where the moon is initially located. Now from that initial line draw two more lines that both go threw the center of the concentric circles with one line 0.6 degrees counter clockwise from the initial line and the other that is 15 degrees counter clockwise away from the initial line. At the beginning of the eclipse, the shadow of the moon is where the initial line that you drew intersects the Earth's circle as I have previously said. In one hour, that point on the Earth's surface has traveled to where the 15 degree line intersects the Earth's circle, while the moon is located where the 0.6 degree line intersects the moon's orbit circle. Now draw a line that goes through where the 0.6 degree line intersects the moon's orbit circle and the sun, and continue that line down to the Earth's surface. Notice that that line intersects the Earth's circle to the West of the place on the Earth's circle where the shadow started. Therefore the shadow has traveled from East to West.
jack
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02/22/2021 11:45 AM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
There is a nice piece of software called 'Celestia' which you can actually enter the date and rotate around the earth/moon/sun in 3d (and the rest of the galaxy if you wish) and you can see how the shadow moves over the earth, pause, look at the positions etc.

You can watch for yourself why it happens.

[link to celestia.space (secure)]
 Quoting: Beneneth


If it has the eclipse shadow traveling from West to East then it is full of shit.
jack
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02/22/2021 11:56 AM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
you left out the orbit of earth in the equation.
Astrodog Jr
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02/22/2021 12:02 PM
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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
I have seen the video and can tell you with certainty that their math is wrong...
leader

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02/22/2021 12:02 PM

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Re: Calling Astro...Please come in and explain how this works???..It's freaking me out.....
you left out the orbit of earth in the equation.
 Quoting: Anonymous Coward 78566342


That does not factor in because the moon travels with the earth, so you can consider it a single reference frame.
jack





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